Blind Luck, the nation&rsquo;s most accomplished 3&#45;year&#45;old filly, will attempt to follow in the footsteps of fellow Kentucky Oaks winner Proud Spell when she travels from her California base to Delaware Park for Saturday&rsquo;s Delaware Oaks.A multiple Grade 1 winner who is 7 for 11 lifetime, Blind Luck will face six rivals and break from post 5 under new rider Joel Rosario in the 59th running of the 1 1/16&#45;mile Delaware Oaks. The Grade 2, $250,000 Oaks goes as race 9 on an 11&#45;race card that includes two $100,000 stakes, the 1 1/16&#45;mile Barbaro for 3&#45;year&#45;olds and the Sussex, a 1 1/16&#45;mile race on the turf.Blind Luck, trained by Jerry Hollendorfer, returns to dirt, where she won the Grade 2 Fantasy at Oaklawn Park and the Grade 1 Kentucky Oaks at Churchill Downs, after a second&#45;place finish over Hollywood Park&rsquo;s synthetic Cushion Track in last month&rsquo;s Hollywood Oaks.It&rsquo;s the second time in three years that the Delaware Oaks has lured the Kentucky Oaks winner. Two years ago, Proud Spell won both the Kentucky and Delaware Oaks en route to earning an Eclipse Award as champion 3&#45;year&#45;old filly.Hollendorfer said he hopes to use the Delaware Oaks as a stepping&#45;stone to the Grade 1 Alabama at Sarataoga on Aug. 21.No Such Word and Havre de Grace, separated by a neck as the one&#45;two finishers in last month&rsquo;s Go for Wand Stakes at Delaware, look like the top challengers to Blind Luck. No Such Word finished nine lengths behind Blind Luck when they met in the April 2 Fantasy.Havre de Grace will be making her graded stakes debut after just missing in her first stakes appearance in the 1 1/16&#45;mile Go for Wand.The Oaks field includes Derwin&rsquo;s Star and Worship the Moon, both stretching out off good efforts sprinting in the $200,000 Jostle at Philadelphia Park. Listen In, a Pennsylvania&#45;bred who just won a first&#45;level allowance, and Calypso Queen, a former maiden claimer still eligible for nonwinners&#45;of&#45;two lifetime, complete the field.